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SQL exercises on soccer Database: Find the teams with other information that finished bottom of their respective groups after conceding four times in three games

SQL soccer Database: Joins Exercise-28 with Solution

28. From the following tables, write a SQL query to find those teams that finished bottom of their respective groups after conceding four times in three games. Return country name, team group and match played.

Sample table: soccer_team


Sample table: soccer_country


Sample Solution:

SQL Code:

SELECT a.country_name as Team , b.team_group,b.match_played, 
b.goal_agnst, b.group_position 
FROM soccer_country a
JOIN soccer_team b
ON a.country_id=b.team_id
WHERE goal_agnst=4 AND group_position=4
ORDER BY team_group;

Sample Output:

  team   | team_group | match_played | goal_agnst | group_position
---------+------------+--------------+------------+----------------
 Romania | A          |            3 |          4 |              4
 Austria | F          |            3 |          4 |              4
(2 rows)

Relational Algebra Expression:

Relational Algebra Expression: Find the teams with other information that finished bottom of their respective groups after conceding four times in three games.

Relational Algebra Tree:

Relational Algebra Tree: Find the teams with other information that finished bottom of their respective groups after conceding four times in three games.

Practice Online


Sample Database: soccer

soccer database relationship structure

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Previous: From the following tables, write a SQL query to find those two teams, scored three goals in a single game in this tournament. Return match number and country name.
Next: From the following tables, write a SQL query to find those players, who contracted to ‘Lyon’ club and participated in the EURO cup 2016 Finals. Return player name, jerseyno, position to play, age, country name.

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SQL: Tips of the Day

SQL Server SELECT into existing table.

INSERT INTO dbo.TABLETWO
SELECT col1, col2
  FROM dbo.TABLEONE
 WHERE col3 LIKE @search_key

This assumes there's only two columns in dbo.TABLETWO - you need to specify the columns otherwise:

INSERT INTO dbo.TABLETWO
  (col1, col2)
SELECT col1, col2
  FROM dbo.TABLEONE
 WHERE col3 LIKE @search_key

Database: SQL Server

Ref: https://bit.ly/3y6tpA3