SQL subqueries on employee Database: List the employees of the grade same as the grade of TUCKER or experience is more than SANDRINE and who are belonging to SYDNEY or PERTH
SQL subqueries on employee Database: Exercise-67 with Solution
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67. From the following table, write a SQL query to find those employees whose grade same as the grade of TUCKER or experience is more than SANDRINE and who are belonging to SYDNEY or PERTH. Return complete information about the employees.
Sample table: employees
Sample table: department
Sample table: salary_grade
Sample Solution:
SELECT *
FROM employees e,
department d,
salary_grade s
WHERE e.dep_id= d.dep_id
AND d.dep_location IN ('SYDNEY',
'PERTH')
AND e.salary BETWEEN s.min_sal AND s.max_sal
AND (s.grade IN
(SELECT s.grade
FROM employees e,
salary_grade s
WHERE e.salary BETWEEN s.min_sal AND s.max_sal
AND e.emp_name = 'TUCKER')
OR age (CURRENT_DATE,hire_date) >
(SELECT age(CURRENT_DATE,hire_date)
FROM employees
WHERE emp_name = 'SANDRINE')) ;
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id | dep_id | dep_name | dep_location | grade | min_sal | max_sal --------+----------+----------+------------+------------+---------+------------+--------+--------+-----------+--------------+-------+---------+--------- 64989 | ADELYN | SALESMAN | 66928 | 1991-02-20 | 1700.00 | 400.00 | 3001 | 3001 | MARKETING | PERTH | 3 | 1501 | 2100 68454 | TUCKER | SALESMAN | 66928 | 1991-09-08 | 1600.00 | 0.00 | 3001 | 3001 | MARKETING | PERTH | 3 | 1501 | 2100 (2 rows)
Practice Online
Structure of employee Database:
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Previous: From the following tables, write a SQL query to find those employees whose salary grade is greater than the grade of MARKER. Return complete information about the employees.
Next: From the following tables, write a SQL query to find those employees whose salary is same as any one of the employee. Return complete information about the employees.
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SQL: Tips of the Day
SQL Server SELECT into existing table.
INSERT INTO dbo.TABLETWO SELECT col1, col2 FROM dbo.TABLEONE WHERE col3 LIKE @search_key
This assumes there's only two columns in dbo.TABLETWO - you need to specify the columns otherwise:
INSERT INTO dbo.TABLETWO (col1, col2) SELECT col1, col2 FROM dbo.TABLEONE WHERE col3 LIKE @search_key
Database: SQL Server
Ref: https://bit.ly/3y6tpA3
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