SQL subqueries on employee Database: Find all the employees who earn the highest salary for a designation and arrange the list in descending order on salary

SQL subqueries on employee Database: Exercise-51 with Solution

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51. From the following table, write a SQL query to find those employees who receive maximum salary for a designation. Sort the result-set in descending order by salary. Return complete information about the employees.

Sample table: employees

Sample Solution:

SELECT *
FROM employees
WHERE salary IN
    (SELECT max(salary)
     FROM employees
     GROUP BY job_name)
ORDER BY salary DESC;

Sample Output:

 emp_id | emp_name | job_name  | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+-----------+------------+------------+---------+------------+--------
  68319 | KAYLING  | PRESIDENT |            | 1991-11-18 | 6000.00 |            |   1001
  67858 | SCARLET  | ANALYST   |      65646 | 1997-04-19 | 3100.00 |            |   2001
  69062 | FRANK    | ANALYST   |      65646 | 1991-12-03 | 3100.00 |            |   2001
  65646 | JONAS    | MANAGER   |      68319 | 1991-04-02 | 2957.00 |            |   2001
  64989 | ADELYN   | SALESMAN  |      66928 | 1991-02-20 | 1700.00 |     400.00 |   3001
  69324 | MARKER   | CLERK     |      67832 | 1992-01-23 | 1400.00 |            |   1001
(6 rows)

Practice Online

Structure of employee Database:

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Previous: From the following table, write a SQL query to find those employees who receive minimum salary for a designation. Sort the result-set in ascending order by salary. Return complete information about the employees.
Next: From the following table, write a SQL query to find recently hired employees of every department. Sort the result-set in descending order by hire date. Return complete information about the employees.