SQL subqueries on employee Database: List all the employees of grade 2 and 3
SQL subqueries on employee Database: Exercise-5 with Solution
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5. From the following table, write a SQL query to find the employees of grade 2 and 3.Return all the information of employees and salary details.
Sample table: employees
Sample table: salary_grade
Sample Solution:
SELECT *
FROM employees e,
salary_grade s
WHERE e.salary BETWEEN s.min_sal AND s.max_sal
AND s.grade IN (2, 3);
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id | grade | min_sal | max_sal --------+----------+----------+------------+------------+---------+------------+--------+-------+---------+--------- 64989 | ADELYN | SALESMAN | 66928 | 1991-02-20 | 1700.00 | 400.00 | 3001 | 3 | 1501 | 2100 65271 | WADE | SALESMAN | 66928 | 1991-02-22 | 1350.00 | 600.00 | 3001 | 2 | 1301 | 1500 66564 | MADDEN | SALESMAN | 66928 | 1991-09-28 | 1350.00 | 1500.00 | 3001 | 2 | 1301 | 1500 68454 | TUCKER | SALESMAN | 66928 | 1991-09-08 | 1600.00 | 0.00 | 3001 | 3 | 1501 | 2100 69324 | MARKER | CLERK | 67832 | 1992-01-23 | 1400.00 | | 1001 | 2 | 1301 | 1500 (5 rows)
Relational Algebra Expression:
Relational Algebra Tree:
Practice Online
Structure of employee Database:
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Previous: From the following tables, write a SQL query to find those employees work at SYDNEY or working in the FINANCE department with an annual salary above 28000, but the monthly salary should not be 3000 or 2800 and who do not work as a MANAGER and whose ID contain a digit of '3' or '7' in 3rd position. Sort the result-set in ascending order by department ID and descending order by job name. Return employee ID, employee name, salary, department name, department location, department ID, and job name.
Next: From the following table, write a SQL query to find those employees of grade 4 or 5 and who work as ANALYST or MANAGER. Return complete information about the employees.
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SQL: Tips of the Day
SQL Server SELECT into existing table.
INSERT INTO dbo.TABLETWO SELECT col1, col2 FROM dbo.TABLEONE WHERE col3 LIKE @search_key
This assumes there's only two columns in dbo.TABLETWO - you need to specify the columns otherwise:
INSERT INTO dbo.TABLETWO (col1, col2) SELECT col1, col2 FROM dbo.TABLEONE WHERE col3 LIKE @search_key
Database: SQL Server
Ref: https://bit.ly/3y6tpA3
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