SQL subqueries on employee Database: List the managers whose salary is more than the average salary of his employees

SQL subqueries on employee Database: Exercise-35 with Solution

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35. From the following table, write a SQL query to find those managers whose salary is more than the average salary of his employees. Return complete information about the employees.

Sample table: employees

Sample Solution:

SELECT *
FROM employees m
WHERE m.emp_id IN
    (SELECT manager_id
     FROM employees)
  AND m.salary >
    (SELECT avg(e.salary)
     FROM employees e
     WHERE e.manager_id = m.emp_id );

Sample Output:

 emp_id | emp_name | job_name  | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+-----------+------------+------------+---------+------------+--------
  67832 | CLARE    | MANAGER   |      68319 | 1991-06-09 | 2550.00 |            |   1001
  69062 | FRANK    | ANALYST   |      65646 | 1991-12-03 | 3100.00 |            |   2001
  68319 | KAYLING  | PRESIDENT |            | 1991-11-18 | 6000.00 |            |   1001
  67858 | SCARLET  | ANALYST   |      65646 | 1997-04-19 | 3100.00 |            |   2001
  66928 | BLAZE    | MANAGER   |      68319 | 1991-05-01 | 2750.00 |            |   3001
(5 rows)

Practice Online

Structure of employee Database:

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Previous: From the following table, write a SQL query to find those employees whose salary is equal or more to the average of maximum and minimum salary. Return complete information about the employees.
Next: From the following table, write a SQL query to find those employees whose salary is less than the salary of his manager but more than the salary of any other manager. Return complete information about the employees.