SQL subqueries on employee Database: Display the list in ascending order of location

SQL subqueries on employee Database: Exercise-3 with Solution

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3. From the following table, write a SQL query to find those employees who work as 'MANAGERS' and 'ANALYST' and working in ‘SYDNEY’ or ‘PERTH’ with an experience more than 5 years without receiving the commission. Sort the result-set in ascending order by department location. Return employee ID, employee name, salary, and department name.

Sample table: employees

Sample table: department

Sample Solution:

SELECT e.emp_id,
       e.emp_name,
       e.salary,
       d.dep_name
FROM employees e,
     department d
WHERE d.dep_location IN ('SYDNEY',
                         'PERTH')
  AND e.dep_id = d.dep_id
  AND e.emp_id IN
    (SELECT e.emp_id
     FROM employees e
     WHERE e.job_name IN ('MANAGER',
                          'ANALYST')
       AND (DATE_PART('year', CURRENT_DATE)-DATE_PART('year', hire_date))> 5
       AND e.commission IS NULL)
ORDER BY d.dep_location ASC;

Sample Output:

 emp_id | emp_name | salary  | dep_name
--------+----------+---------+-----------
  66928 | BLAZE    | 2750.00 | MARKETING
  67832 | CLARE    | 2550.00 | FINANCE
(2 rows)

Practice Online

Structure of employee Database

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Previous: From the following table, write a SQL query to compute the experience of all the managers. Return employee ID, employee name, job name, joining date, and experience.
Next: From the following table, write a SQL query to find those employees work at SYDNEY or working in the FINANCE department with an annual salary above 28000, but the monthly salary should not be 3000 or 2800 and who do not work as a MANAGER and whose ID contain a digit of '3' or '7' in 3rd position. Sort the result-set in ascending order by department ID and descending order by job name. Return employee ID, employee name, salary, department name, department location, department ID, and job name.