SQL subqueries on employee Database: List the employees whose designation is same as the designation of SANDRINE or ADELYN
SQL subqueries on employee Database: Exercise-16 with Solution
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16. From the following table, write a SQL query to find those employees whose designation is same as the designation of SANDRINE or ADELYN. Return complete information about the employees.
Sample table: employees
Sample Solution:
SELECT *
FROM employees
WHERE job_name IN
(SELECT job_name
FROM employees
WHERE emp_name = 'SANDRINE'
OR emp_name = 'ADELYN');
OR
SELECT *
FROM employees
WHERE job_name IN
(SELECT job_name
FROM employees
WHERE emp_name IN('SANDRINE',
'ADELYN'));
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+----------+------------+------------+---------+------------+-------- 63679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001 64989 | ADELYN | SALESMAN | 66928 | 1991-02-20 | 1700.00 | 400.00 | 3001 65271 | WADE | SALESMAN | 66928 | 1991-02-22 | 1350.00 | 600.00 | 3001 66564 | MADDEN | SALESMAN | 66928 | 1991-09-28 | 1350.00 | 1500.00 | 3001 68454 | TUCKER | SALESMAN | 66928 | 1991-09-08 | 1600.00 | 0.00 | 3001 68736 | ADNRES | CLERK | 67858 | 1997-05-23 | 1200.00 | | 2001 69000 | JULIUS | CLERK | 66928 | 1991-12-03 | 1050.00 | | 3001 69324 | MARKER | CLERK | 67832 | 1992-01-23 | 1400.00 | | 1001 (8 rows)
Practice Online
Structure of employee Database:
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Previous: From the following table, write a SQL query to find those employees of grade 3 and 4 and work in the department of FINANCE or AUDIT and whose salary is more than the salary of ADELYN and experience is more than FRANK. Return complete information about the employees.
Next: From the following table, write a SQL query to list any job of department ID 1001 which are not found in department ID 2001. Return job name.
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SQL: Tips of the Day
SQL Server SELECT into existing table.
INSERT INTO dbo.TABLETWO SELECT col1, col2 FROM dbo.TABLEONE WHERE col3 LIKE @search_key
This assumes there's only two columns in dbo.TABLETWO - you need to specify the columns otherwise:
INSERT INTO dbo.TABLETWO (col1, col2) SELECT col1, col2 FROM dbo.TABLEONE WHERE col3 LIKE @search_key
Database: SQL Server
Ref: https://bit.ly/3y6tpA3
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