SQL subqueries on employee Database: List the employees whose designation are same as the designation of MARKER or salary is more than the salary of ADELYN.
SQL subqueries on employee Database: Exercise-12 with Solution
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12. From the following table, write a SQL query to find those employees whose designation are the same as the designation of MARKER or salary is more than the salary of ADELYN. Return complete information about the employees.
Sample table: employees
Sample Solution:
SELECT *
FROM employees
WHERE job_name =
(SELECT job_name
FROM employees
WHERE emp_name = 'MARKER' )
OR salary>
(SELECT salary
FROM employees
WHERE emp_name = 'ADELYN');
Sample Output:
emp_id | emp_name | job_name | manager_id | hire_date | salary | commission | dep_id --------+----------+-----------+------------+------------+---------+------------+-------- 68319 | KAYLING | PRESIDENT | | 1991-11-18 | 6000.00 | | 1001 66928 | BLAZE | MANAGER | 68319 | 1991-05-01 | 2750.00 | | 3001 67832 | CLARE | MANAGER | 68319 | 1991-06-09 | 2550.00 | | 1001 65646 | JONAS | MANAGER | 68319 | 1991-04-02 | 2957.00 | | 2001 67858 | SCARLET | ANALYST | 65646 | 1997-04-19 | 3100.00 | | 2001 69062 | FRANK | ANALYST | 65646 | 1991-12-03 | 3100.00 | | 2001 63679 | SANDRINE | CLERK | 69062 | 1990-12-18 | 900.00 | | 2001 68736 | ADNRES | CLERK | 67858 | 1997-05-23 | 1200.00 | | 2001 69000 | JULIUS | CLERK | 66928 | 1991-12-03 | 1050.00 | | 3001 69324 | MARKER | CLERK | 67832 | 1992-01-23 | 1400.00 | | 1001 (10 rows)
Practice Online
Structure of employee Database:
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Previous: From the following table, write a SQL query to find those employees whose salary is the same as the salary of FRANK or SANDRINE. Sort the result-set in descending order by salary. Return complete information about the employees.
Next: From the following table, write a SQL query to find those employees whose salary is more than the total remuneration (salary + commission) of the designation SALESMAN. Return complete information about the employees.
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SQL: Tips of the Day
SQL Server SELECT into existing table.
INSERT INTO dbo.TABLETWO SELECT col1, col2 FROM dbo.TABLEONE WHERE col3 LIKE @search_key
This assumes there's only two columns in dbo.TABLETWO - you need to specify the columns otherwise:
INSERT INTO dbo.TABLETWO (col1, col2) SELECT col1, col2 FROM dbo.TABLEONE WHERE col3 LIKE @search_key
Database: SQL Server
Ref: https://bit.ly/3y6tpA3
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