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SQL exercises on employee Database: List the total information of employees table along with department, and location of all the employees working under FINANCE and AUDIT in the ascending department no

SQL employee Database: Exercise-82 with Solution

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82. From the following tables, write a SQL query to find the location of all the employees working in FINANCE or AUDIT department. Sort the result-set in ascending order by department ID. Return complete information about the employees.

Pictorial Presentation:

SQL exercises on employee Database: List the total information of employees table along with department, and location of all the employees working under FINANCE and AUDIT in the ascending department no

Sample table: employees


Sample table: department


Sample Solution:

SELECT *
FROM employees e,
     department d
WHERE (dep_name = 'FINANCE'
       OR dep_name ='AUDIT')
  AND e.dep_id = d.dep_id
ORDER BY e.dep_id ASC;

OR

SELECT *
FROM employees e,
     department d
WHERE d.dep_name IN ('FINANCE',
                     'AUDIT')
  AND e.dep_id = d.dep_id
ORDER BY e.dep_id ASC;

Sample Output:

 emp_id | emp_name | job_name  | manager_id | hire_date  | salary  | commission | dep_id | dep_id | dep_name | dep_location
--------+----------+-----------+------------+------------+---------+------------+--------+--------+----------+--------------
  68319 | KAYLING  | PRESIDENT |            | 1991-11-18 | 6000.00 |            |   1001 |   1001 | FINANCE  | SYDNEY
  67832 | CLARE    | MANAGER   |      68319 | 1991-06-09 | 2550.00 |            |   1001 |   1001 | FINANCE  | SYDNEY
  69324 | MARKER   | CLERK     |      67832 | 1992-01-23 | 1400.00 |            |   1001 |   1001 | FINANCE  | SYDNEY
  67858 | SCARLET  | ANALYST   |      65646 | 1997-04-19 | 3100.00 |            |   2001 |   2001 | AUDIT    | MELBOURNE
  69062 | FRANK    | ANALYST   |      65646 | 1991-12-03 | 3100.00 |            |   2001 |   2001 | AUDIT    | MELBOURNE
  63679 | SANDRINE | CLERK     |      69062 | 1990-12-18 |  900.00 |            |   2001 |   2001 | AUDIT    | MELBOURNE
  68736 | ADNRES   | CLERK     |      67858 | 1997-05-23 | 1200.00 |            |   2001 |   2001 | AUDIT    | MELBOURNE
  65646 | JONAS    | MANAGER   |      68319 | 1991-04-02 | 2957.00 |            |   2001 |   2001 | AUDIT    | MELBOURNE
(8 rows)

Relational Algebra Expression:

Relational Algebra Expression: List the total information of employees table along with department, and location of all the employees working under FINANCE and AUDIT in the ascending department no.

Relational Algebra Tree:

Relational Algebra Tree: List the total information of employees table along with department, and location of all the employees working under FINANCE and AUDIT in the ascending department no.

Practice Online


Sample Database: employee

employee database structure

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Previous: From the following table, write a SQL query to list the employees in ascending order of designations of those joined after the second half of 1991.
Next: From the following tables, write a SQL query to find the employees along with grades in ascending order. Return complete information about the employees.

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SQL: Tips of the Day

SQL Server SELECT into existing table.

INSERT INTO dbo.TABLETWO
SELECT col1, col2
  FROM dbo.TABLEONE
 WHERE col3 LIKE @search_key

This assumes there's only two columns in dbo.TABLETWO - you need to specify the columns otherwise:

INSERT INTO dbo.TABLETWO
  (col1, col2)
SELECT col1, col2
  FROM dbo.TABLEONE
 WHERE col3 LIKE @search_key

Database: SQL Server

Ref: https://bit.ly/3y6tpA3