SQL exercises on employee Database: List the employees in ascending order of seniority who joined on 1-MAY-91,or 3-DEC-91, or 19-JAN-90

SQL employee Database: Exercise-72 with Solution

[An editor is available at the bottom of the page to write and execute the scripts.]

72. From the following table, write a SQL query to find those employees who joined on 1-MAY-91, or 3-DEC-91, or 19-JAN-90. Sort the result-set in ascending order by hire date. Return complete information about the employees.

Pictorial Presentation:

Sample table: employees

Sample Solution:

SELECT *
FROM employees
WHERE hire_date IN ('1991-5-01',
                    '1991-12-03',
                    '1990-01-19')
ORDER BY hire_date ASC;

Sample Output:

 emp_id | emp_name | job_name | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+----------+------------+------------+---------+------------+--------
  66928 | BLAZE    | MANAGER  |      68319 | 1991-05-01 | 2750.00 |            |   3001
  69062 | FRANK    | ANALYST  |      65646 | 1991-12-03 | 3100.00 |            |   2001
  69000 | JULIUS   | CLERK    |      66928 | 1991-12-03 | 1050.00 |            |   3001
(3 rows)

Relational Algebra Expression:

Relational Algebra Tree:

Practice Online

Sample Database: employee

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: From the following table, write a SQL query to find the department location of employee ‘CLARE’. Return department location.
Next: From the following table, write a SQL query to find those employees who draw salary less than 1000. Sort the result-set in ascending order by salary. Return complete information about the employees.