SQL exercises on employee Database: List the employees name, department, salary and commission. For those whose salary is between 2000 and 5000 while location is PERTH
SQL employee Database: Exercise-55 with Solution
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55. From the following table, write a SQL query to find those employees whose salary is between 2000 and 5000 (Begin and end values are included.) and location is PERTH. Return employee name, department ID, salary, and commission.
Sample table: employees
Sample table: department
Pictorial Presentation:
Sample Solution:
SELECT e.emp_name,
e.dep_id,
e.salary,
e.commission
FROM employees e,
department d
WHERE e.dep_id = d.dep_id
AND d.dep_location = 'PERTH'
AND e.salary BETWEEN 2000 AND 5000;
Sample Output:
emp_name | dep_id | salary | commission ----------+--------+---------+------------ BLAZE | 3001 | 2750.00 | (1 row)
Relational Algebra Expression:
Relational Algebra Tree:
Practice Online
Sample Database: employee
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Previous: From the following table, write a SQL query to find those employees whose salary is higher than the salary of their managers. Return employee name, job name, manager ID, salary, manager name, manager's salary.
Next: From the following table, write a SQL query to find those employees whose department ID is 1001 or 3001 and salary grade is not 4. They joined the company before 1992-12-31. Return grade, employee name.
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SQL: Tips of the Day
SQL Server SELECT into existing table.
INSERT INTO dbo.TABLETWO SELECT col1, col2 FROM dbo.TABLEONE WHERE col3 LIKE @search_key
This assumes there's only two columns in dbo.TABLETWO - you need to specify the columns otherwise:
INSERT INTO dbo.TABLETWO (col1, col2) SELECT col1, col2 FROM dbo.TABLEONE WHERE col3 LIKE @search_key
Database: SQL Server
Ref: https://bit.ly/3y6tpA3
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