SQL exercises on employee Database: List the employees along with department name

SQL employee Database: Exercise-52 with Solution

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52. From the following table, write a SQL query to find employees along with department name. Return employee ID, employee name, job name, manager ID, hire date, salary, commission, department ID, and department name.

Sample table: employees

Sample table: department

Pictorial Presentation:

Sample Solution:

SELECT e.emp_id,
       e.emp_name,
       e.job_name,
       e.manager_id,
       e.hire_date,
       e.salary,
       e.commission,
       e.dep_id,
       d.dep_name
FROM employees e,
     department d
WHERE e.dep_id = d.dep_id;

Sample Output:

 emp_id | emp_name | job_name  | manager_id | hire_date  | salary  | commission | dep_id | dep_name
--------+----------+-----------+------------+------------+---------+------------+--------+----------
  68319 | KAYLING  | PRESIDENT |            | 1991-11-18 | 6000.00 |            |   1001 | FINANCE
  66928 | BLAZE    | MANAGER   |      68319 | 1991-05-01 | 2750.00 |            |   3001 | MARKETING
  67832 | CLARE    | MANAGER   |      68319 | 1991-06-09 | 2550.00 |            |   1001 | FINANCE
  65646 | JONAS    | MANAGER   |      68319 | 1991-04-02 | 2957.00 |            |   2001 | AUDIT
  67858 | SCARLET  | ANALYST   |      65646 | 1997-04-19 | 3100.00 |            |   2001 | AUDIT
  69062 | FRANK    | ANALYST   |      65646 | 1991-12-03 | 3100.00 |            |   2001 | AUDIT
  63679 | SANDRINE | CLERK     |      69062 | 1990-12-18 |  900.00 |            |   2001 | AUDIT
  64989 | ADELYN   | SALESMAN  |      66928 | 1991-02-20 | 1700.00 |     400.00 |   3001 | MARKETING
  65271 | WADE     | SALESMAN  |      66928 | 1991-02-22 | 1350.00 |     600.00 |   3001 | MARKETING
  66564 | MADDEN   | SALESMAN  |      66928 | 1991-09-28 | 1350.00 |    1500.00 |   3001 | MARKETING
  68454 | TUCKER   | SALESMAN  |      66928 | 1991-09-08 | 1600.00 |       0.00 |   3001 | MARKETING
  68736 | ADNRES   | CLERK     |      67858 | 1997-05-23 | 1200.00 |            |   2001 | AUDIT
  69000 | JULIUS   | CLERK     |      66928 | 1991-12-03 | 1050.00 |            |   3001 | MARKETING
  69324 | MARKER   | CLERK     |      67832 | 1992-01-23 | 1400.00 |            |   1001 | FINANCE
(14 rows)

Relational Algebra Expression:

Relational Algebra Tree:

Practice Online

Sample Database: employee

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Previous: From the following table, write a SQL query to find those employees who joined before or after the year 1991. Return complete information about the employees.
Next: From the following tables, write a SQL query to find those employees who earn 60000 in a year or not working as an ANALYST. Return employee name, job name, (12*salary) as Annual Salary, department ID, and grade.