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SQL exercises on employee Database: List the employees working under the managers 63679,68319,66564,69000

SQL employee Database: Exercise-46 with Solution

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46. From the following table, write a SQL query to find those employees working under the managers 63679 or 68319 or 66564 or 69000. Return complete information about the employees.

Sample table: employees


Pictorial Presentation:

SQL exercises on employee Database: List the employees working under the managers 63679,68319,66564,69000

Sample Solution:

SELECT *
FROM employees
WHERE manager_id IN (63679,
                     68319,
                     66564,
                     69000);

Sample Output:

 emp_id | emp_name | job_name | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+----------+------------+------------+---------+------------+--------
  66928 | BLAZE    | MANAGER  |      68319 | 1991-05-01 | 2750.00 |            |   3001
  67832 | CLARE    | MANAGER  |      68319 | 1991-06-09 | 2550.00 |            |   1001
  65646 | JONAS    | MANAGER  |      68319 | 1991-04-02 | 2957.00 |            |   2001
(3 rows)

Relational Algebra Expression:

Relational Algebra Expression: List the employees working under the managers 63679,68319,66564,69000.

Relational Algebra Tree:

Relational Algebra Tree: List the employees working under the managers 63679,68319,66564,69000.

Practice Online


Sample Database: employee

employee database structure

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Previous: From the following table, write a SQL query to find all those employees who have joined on 1st May, 20th Feb, and 3rd Dec in the year 1991. Return complete information about the employees.
Next: From the following table, write a SQL query to find those employees who joined after the month JUNE in the year 1991 and within this year. Return complete information about the employees.

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SQL: Tips of the Day

SQL Server SELECT into existing table. 

INSERT INTO dbo.TABLETWO
SELECT col1, col2
  FROM dbo.TABLEONE
 WHERE col3 LIKE @search_key

This assumes there's only two columns in dbo.TABLETWO - you need to specify the columns otherwise:

INSERT INTO dbo.TABLETWO
  (col1, col2)
SELECT col1, col2
  FROM dbo.TABLEONE
 WHERE col3 LIKE @search_key

Database: SQL Server

Ref: https://bit.ly/3y6tpA3