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SQL exercises on employee Database: Display all the details of the employees whose commission is more than their salary

SQL employee Database: Exercise-15 with Solution

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15. From the following table, write a SQL query to find those employees whose commission is more than their salary. Return complete information about the employees.

Sample table: employees


Pictorial Presentation:

SQL exercises on employee Database: Display all the details of the employees whose commission is more than their salary.

Sample Solution:

SELECT *
FROM employees
WHERE commission>salary;

Sample Output:

 emp_id | emp_name | job_name | manager_id | hire_date  | salary  | commission | dep_id
--------+----------+----------+------------+------------+---------+------------+--------
  66564 | MADDEN   | SALESMAN |      66928 | 1991-09-28 | 1350.00 |    1500.00 |   3001
(1 row)

Relational Algebra Expression:

Relational Algebra Expression: Display all the details of the employees whose commission is more than their salary.

Relational Algebra Tree:

Relational Algebra Tree: Display all the details of the employees whose commission is more than their salary.

Practice Online


Sample Database: employee

employee database structure

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Previous: From the following table, write a SQL query to find the details of the employee ‘BLAZE’.
Next: From the following table, write a SQL query to find those employees whose salary exceeds 3000 after giving 25% increment. Return complete information about the employees.

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SQL: Tips of the Day

SQL Server SELECT into existing table. 

INSERT INTO dbo.TABLETWO
SELECT col1, col2
  FROM dbo.TABLEONE
 WHERE col3 LIKE @search_key

This assumes there's only two columns in dbo.TABLETWO - you need to specify the columns otherwise:

INSERT INTO dbo.TABLETWO
  (col1, col2)
SELECT col1, col2
  FROM dbo.TABLEONE
 WHERE col3 LIKE @search_key

Database: SQL Server

Ref: https://bit.ly/3y6tpA3