Python: Create a symmetric difference
Python sets: Exercise-9 with Solution
Write a Python program to create a symmetric difference.
From Wikipedia,
In mathematics, the symmetric difference, also known as the disjunctive union, of two sets is the set of elements which are in either of the sets and not in their intersection. The symmetric difference of the sets A and B is commonly denoted by
For example, the symmetric difference of the sets {1,2,3} and {3,4} is {1,2,4}.
Sample Solution-1:
Using symmetric_difference() Method
Python Code:
setc1 = set(["green", "blue"])
setc2 = set(["blue", "yellow"])
print("Original sets:")
print(setc1)
print(setc2)
r1 = setc1.symmetric_difference(setc2)
print("\nSymmetric difference of setc1 - setc2:")
print(r1)
r2 = setc2.symmetric_difference(setc1)
print("\nSymmetric difference of setc2 - setc1:")
print(r2)
setn1 = set([1, 1, 2, 3, 4, 5])
setn2 = set([1, 5, 6, 7, 8, 9])
print("\nOriginal sets:")
print(setn1)
print(setn2)
r1 = setn1.symmetric_difference(setn2)
print("\nSymmetric difference of setn1 - setn2:")
print(r1)
r2 = setn2.symmetric_difference(setn1)
print("\nSymmetric difference of setn2 - setn1:")
print(r2)
Sample Output:
Original sets: {'blue', 'green'} {'blue', 'yellow'} Symmetric difference of setc1 - setc2: {'yellow', 'green'} Symmetric difference of setc2 - setc1: {'yellow', 'green'} Original sets: {1, 2, 3, 4, 5} {1, 5, 6, 7, 8, 9} Symmetric difference of setn1 - setn2: {2, 3, 4, 6, 7, 8, 9} Symmetric difference of setn2 - setn1: {2, 3, 4, 6, 7, 8, 9}
Pictorial Presentation:
Visualize Python code execution:
The following tool visualize what the computer is doing step-by-step as it executes the said program:
Sample Solution-2:
Using symmetric difference operator(^)
Python Code:
setc1 = set(["green", "blue"])
setc2 = set(["blue", "yellow"])
print("Original sets:")
print(setc1)
print(setc2)
r1 = setc1^setc2
print("\nSymmetric difference of setc1 - setc2:")
print(r1)
r2 = setc2^setc1
print("\nSymmetric difference of setc2 - setc1:")
print(r2)
setn1 = set([1, 1, 2, 3, 4, 5])
setn2 = set([1, 5, 6, 7, 8, 9])
print("\nOriginal sets:")
print(setn1)
print(setn2)
r1 = setn1^setn2
print("\nSymmetric difference of setn1 - setn2:")
print(r1)
r2 = setn2^setn1
print("\nSymmetric difference of setn2 - setn1:")
print(r2)
Sample Output:
Original sets: {'blue', 'green'} {'yellow', 'blue'} Symmetric difference of setc1 - setc2: {'yellow', 'green'} Symmetric difference of setc2 - setc1: {'yellow', 'green'} Original sets: {1, 2, 3, 4, 5} {1, 5, 6, 7, 8, 9} Symmetric difference of setn1 - setn2: {2, 3, 4, 6, 7, 8, 9} Symmetric difference of setn2 - setn1: {2, 3, 4, 6, 7, 8, 9}
Pictorial Presentation:
Visualize Python code execution:
The following tool visualize what the computer is doing step-by-step as it executes the said program:
Python Code Editor:
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Python: Tips of the Day
Find current directory and file's directory:
To get the full path to the directory a Python file is contained in, write this in that file:
import os dir_path = os.path.dirname(os.path.realpath(__file__))
(Note that the incantation above won't work if you've already used os.chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os.chdir() call.)
To get the current working directory use
import os cwd = os.getcwd()
Documentation references for the modules, constants and functions used above:
- The os and os.path modules.
- The __file__ constant
- os.path.realpath(path) (returns "the canonical path of the specified filename, eliminating any symbolic links encountered in the path")
- os.path.dirname(path) (returns "the directory name of pathname path")
- os.getcwd() (returns "a string representing the current working directory")
- os.chdir(path) ("change the current working directory to path")
Ref: https://bit.ly/3fy0R6m
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