Python: Find files and skip directories of a given directory

Last update on May 28 2022 13:01:21 (UTC/GMT +8 hours)

Python Basic: Exercise-136 with Solution

Write a Python program to find files and skip directories of a given directory.

Sample Solution-1:

Python Code:

import os
print([f for f in os.listdir('/home/students') if os.path.isfile(os.path.join('/home/students', f))])

Sample Output:

['test.txt', '.mysql_history', '.bash_logout', '.bash_history', '.profile', 'abc.py', '.viminfo', 'mynewtest.t
xt', 'myfile.txt', 'logging_example.out', '.web-term.json', 'abc.txt', '64a57280-272f-11e7-9ce4-832a8e030fef.p
y', 'exercise.cs', '.bashrc', 'Example.cs', 'myfig.png', 'file.out', 'line.gif', 'mmm.txt\n', 'temp.txt', 'ddd
d.txt\n', 'sss.dat\n', 'result.txt', 'output.jpg', '26492-1274250701.png', 'mytest.txt']

Sample Solution-2:

Python Code:

import os
user_path = 'd:/'
for fname in os.listdir(user_path):
   path = os.path.join(user_path, fname)
   if os.path.isdir(path):
       # skip directories
       continue
   # print the file names
   print(fname)

Sample Output:

5C90A0D8.tmp
abcd.txt
BMCASSET.zip
computer.png
Dreamweaver 8.zip
Dreamweaver8-en.zip
eula.1028.txt
eula.1031.txt
eula.1033.txt
eula.1036.txt
eula.1040.txt
eula.1041.txt
eula.1042.txt
eula.2052.txt
eula.3082.txt
ezgif.com-gif-maker.png
globdata.ini
How To Use Sets in Python (Python Tutorial .mp4
hr
index.html
install.exe
install.ini
install.res.1028.dll
install.res.1031.dll
install.res.1033.dll
install.res.1036.dll
install.res.1040.dll
install.res.1041.dll
install.res.1042.dll
install.res.2052.dll
install.res.3082.dll
java-array-exercise-flowchart-35.png
LICENSE
Local Disk (C) - Shortcut.lnk
Main.java
math_expression_commands.txt
msdia80.dll
pandas-series-loc-7 (2).zip
psr (Autosaved).xlsx
psr.xlsx
script.js
share-mutualfund.xlsx
sqlite3.def
sqlite3.dll
vcredist.bmp
VC_RED.cab
VC_RED.MSI
visustin.txt
w3resource-logo.png

Python Code Editor:

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Python: Tips of the Day

Find current directory and file's directory:

To get the full path to the directory a Python file is contained in, write this in that file:

import os dir_path = os.path.dirname(os.path.realpath(__file__))

(Note that the incantation above won't work if you've already used os.chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os.chdir() call.)

To get the current working directory use

import os cwd = os.getcwd()

Documentation references for the modules, constants and functions used above:

The os and os.path modules.

The __file__ constant

os.path.realpath(path) (returns "the canonical path of the specified filename, eliminating any symbolic links encountered in the path")

os.path.dirname(path) (returns "the directory name of pathname path")

os.getcwd() (returns "a string representing the current working directory")

os.chdir(path) ("change the current working directory to path")

Ref: https://bit.ly/3fy0R6m