Pandas: Index of certain element of a Series
Pandas Indexing: Exercise-18 with Solution
Write a Pandas program to get the index of an element of a given Series.
Sample Solution:
Python Code :
import pandas as pd
ds = pd.Series([1,3,5,7,9,11,13,15], index=[0,1,2,3,4,5,7,8])
print("Original Series:")
print(ds)
print("\nIndex of 11 in the said series:")
x = ds[ds == 11].index[0]
print(x)
Sample Output:
Original Series: 0 1 1 3 2 5 3 7 4 9 5 11 7 13 8 15 dtype: int64 Index of 11 in the said series: 5
Python Code Editor:
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Python: Tips of the Day
Find current directory and file's directory:
To get the full path to the directory a Python file is contained in, write this in that file:
import os dir_path = os.path.dirname(os.path.realpath(__file__))
(Note that the incantation above won't work if you've already used os.chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os.chdir() call.)
To get the current working directory use
import os cwd = os.getcwd()
Documentation references for the modules, constants and functions used above:
- The os and os.path modules.
- The __file__ constant
- os.path.realpath(path) (returns "the canonical path of the specified filename, eliminating any symbolic links encountered in the path")
- os.path.dirname(path) (returns "the directory name of pathname path")
- os.getcwd() (returns "a string representing the current working directory")
- os.chdir(path) ("change the current working directory to path")
Ref: https://bit.ly/3fy0R6m
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