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NumPy: Find point by point distances of a random vector with shape (10,2) representing coordinates

NumPy: Random Exercise-12 with Solution

Write a NumPy program to find point by point distances of a random vector with shape (10,2) representing coordinates.

Sample Solution :-

Python Code :

import numpy as np
a= np.random.random((10,2))
x,y = np.atleast_2d(a[:,0], a[:,1])
d = np.sqrt( (x-x.T)**2 + (y-y.T)**2)
print(d)

Sample Output:

[[ 0.          0.42309206  0.59799949  0.44076341  0.64568848  0.53547789                                                                     
   0.39263926  0.38982854  0.39228612  0.44529689]                     
 [ 0.42309206  0.          1.0208224   0.38421553  0.92200913  0.73182405                                                                     
   0.73513877  0.80796679  0.64687549  0.73308548]                     
 [ 0.59799949  1.0208224   0.          0.94341451  0.66895368  0.71852306                                                                     
   0.48605697  0.22453123  0.64173589  0.55440442]                     
 [ 0.44076341  0.38421553  0.94341451  0.          0.60846866  0.9467662                                                                      
   0.51350109  0.78044594  0.36885259  0.88113793]                     
 [ 0.64568848  0.92200913  0.66895368  0.60846866  0.          1.12199998                                                                     
   0.27042981  0.66189707  0.27709162  0.98097303]                     
 [ 0.53547789  0.73182405  0.71852306  0.9467662   1.12199998  0.      
   0.85159212  0.53429835  0.90830578  0.1651062 ]                     
 [ 0.39263926  0.73513877  0.48605697  0.51350109  0.27042981  0.85159212                                                                     
   0.          0.41507505  0.16091134  0.71215345]                     
 [ 0.38982854  0.80796679  0.22453123  0.78044594  0.66189707  0.53429835                                                                     
   0.41507505  0.          0.54198973  0.370672  ]                     
 [ 0.39228612  0.64687549  0.64173589  0.36885259  0.27709162  0.90830578                                                                     
   0.16091134  0.54198973  0.          0.78707458]                     
 [ 0.44529689  0.73308548  0.55440442  0.88113793  0.98097303  0.1651062                                                                      
   0.71215345  0.370672    0.78707458  0.        ]]

Python-Numpy Code Editor:

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Python: Tips of the Day

Find current directory and file's directory:

To get the full path to the directory a Python file is contained in, write this in that file:

import os 
dir_path = os.path.dirname(os.path.realpath(__file__))

(Note that the incantation above won't work if you've already used os.chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os.chdir() call.)

To get the current working directory use

import os
cwd = os.getcwd()

Documentation references for the modules, constants and functions used above:

  • The os and os.path modules.
  • The __file__ constant
  • os.path.realpath(path) (returns "the canonical path of the specified filename, eliminating any symbolic links encountered in the path")
  • os.path.dirname(path) (returns "the directory name of pathname path")
  • os.getcwd() (returns "a string representing the current working directory")
  • os.chdir(path) ("change the current working directory to path")

Ref: https://bit.ly/3fy0R6m