Python Math: Reverse a range
Python Math: Exercise-71 with Solution
Write a Python program to reverse a range.
Sample Solution:-
Python Code:
#https://gist.github.com/fcicq/ddb746042150b4e959e6
def reversed_range(start, stop=None, step=1):
if stop is None:
return range(start - step, -step, -step)
else:
new_start = stop - ((stop-start-1) % step + 1)
new_end = new_start - (stop-start+step-1) // step * step
if (stop - start) % step == 0 and step < 0: new_start -= step
return range(new_start, new_end, -step)
print(reversed_range(1, 10, 2))
print(reversed_range(1, 5, 1))
Sample Output:
range(9, -1, -2) range(4, 0, -1)
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Python: Tips of the Day
Find current directory and file's directory:
To get the full path to the directory a Python file is contained in, write this in that file:
import os dir_path = os.path.dirname(os.path.realpath(__file__))
(Note that the incantation above won't work if you've already used os.chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os.chdir() call.)
To get the current working directory use
import os cwd = os.getcwd()
Documentation references for the modules, constants and functions used above:
- The os and os.path modules.
- The __file__ constant
- os.path.realpath(path) (returns "the canonical path of the specified filename, eliminating any symbolic links encountered in the path")
- os.path.dirname(path) (returns "the directory name of pathname path")
- os.getcwd() (returns "a string representing the current working directory")
- os.chdir(path) ("change the current working directory to path")
Ref: https://bit.ly/3fy0R6m
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