Python: Change the position of every n-th value with the (n+1)th in a list
Python List: Exercise - 38 with Solution
Write a Python program to change the position of every n-th value with the (n+1)th in a list.
Sample Solution:-
Python Code:
from itertools import zip_longest, chain, tee
def replace2copy(lst):
lst1, lst2 = tee(iter(lst), 2)
return list(chain.from_iterable(zip_longest(lst[1::2], lst[::2])))
n = [0,1,2,3,4,5]
print(replace2copy(n))
Sample Output:
[1, 0, 3, 2, 5, 4]
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Python: Tips of the Day
Find current directory and file's directory:
To get the full path to the directory a Python file is contained in, write this in that file:
import os dir_path = os.path.dirname(os.path.realpath(__file__))
(Note that the incantation above won't work if you've already used os.chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os.chdir() call.)
To get the current working directory use
import os cwd = os.getcwd()
Documentation references for the modules, constants and functions used above:
- The os and os.path modules.
- The __file__ constant
- os.path.realpath(path) (returns "the canonical path of the specified filename, eliminating any symbolic links encountered in the path")
- os.path.dirname(path) (returns "the directory name of pathname path")
- os.getcwd() (returns "a string representing the current working directory")
- os.chdir(path) ("change the current working directory to path")
Ref: https://bit.ly/3fy0R6m
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