Python: Find the difference between elements (n+1th – nth) of a given list of numeric values
Python List: Exercise - 118 with Solution
Write a Python program to find the difference between elements (n+1th – nth) of a given list of numeric values.
Sample Solution:
Python Code:
def elements_difference(nums):
result = [j-i for i, j in zip(nums[:-1], nums[1:])]
return result
nums1 = [1,2,3,4,5,6,7,8,9,10]
nums2 = [2,4,6,8]
print("Original list:")
print(nums1)
print("\nDfference between elements (n+1th – nth) of the said list :")
print(elements_difference(nums1))
print("\nOriginal list:")
print(nums2)
print("\nDfference between elements (n+1th – nth) of the said list :")
print(elements_difference(nums2))
Sample Output:
Original list: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] Dfference between elements (n+1th – nth) of the said list : [1, 1, 1, 1, 1, 1, 1, 1, 1] Original list: [2, 4, 6, 8] Dfference between elements (n+1th – nth) of the said list : [2, 2, 2]
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Python: Tips of the Day
Find current directory and file's directory:
To get the full path to the directory a Python file is contained in, write this in that file:
import os dir_path = os.path.dirname(os.path.realpath(__file__))
(Note that the incantation above won't work if you've already used os.chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os.chdir() call.)
To get the current working directory use
import os cwd = os.getcwd()
Documentation references for the modules, constants and functions used above:
- The os and os.path modules.
- The __file__ constant
- os.path.realpath(path) (returns "the canonical path of the specified filename, eliminating any symbolic links encountered in the path")
- os.path.dirname(path) (returns "the directory name of pathname path")
- os.getcwd() (returns "a string representing the current working directory")
- os.chdir(path) ("change the current working directory to path")
Ref: https://bit.ly/3fy0R6m
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