Python: Find numbers within a given range where every number is divisible by every digit it contains
Python Lambda: Exercise-24 with Solution
Write a Python program to find numbers within a given range where every number is divisible by every digit it contains.
Sample Solution:
Python Code :
def divisible_by_digits(start_num, end_num):
return [n for n in range(start_num, end_num+1) \
if not any(map(lambda x: int(x) == 0 or n%int(x) != 0, str(n)))]
print(divisible_by_digits(1,22))
Sample Output:
[1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22]
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Previous: Write a Python program to calculate the sum of the positive and negative numbers of a given list of numbers using lambda function.
Next: Write a Python program to create the next bigger number by rearranging the digits of a given number.
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Python: Tips of the Day
Find current directory and file's directory:
To get the full path to the directory a Python file is contained in, write this in that file:
import os dir_path = os.path.dirname(os.path.realpath(__file__))
(Note that the incantation above won't work if you've already used os.chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os.chdir() call.)
To get the current working directory use
import os cwd = os.getcwd()
Documentation references for the modules, constants and functions used above:
- The os and os.path modules.
- The __file__ constant
- os.path.realpath(path) (returns "the canonical path of the specified filename, eliminating any symbolic links encountered in the path")
- os.path.dirname(path) (returns "the directory name of pathname path")
- os.getcwd() (returns "a string representing the current working directory")
- os.chdir(path) ("change the current working directory to path")
Ref: https://bit.ly/3fy0R6m
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