Python: Count the even, odd numbers in a given array of integers using Lambda
Python Lambda: Exercise-13 with Solution
Write a Python program to count the even, odd numbers in a given array of integers using Lambda.
Sample Solution:
Python Code :
array_nums = [1, 2, 3, 5, 7, 8, 9, 10]
print("Original arrays:")
print(array_nums)
odd_ctr = len(list(filter(lambda x: (x%2 != 0) , array_nums)))
even_ctr = len(list(filter(lambda x: (x%2 == 0) , array_nums)))
print("\nNumber of even numbers in the above array: ", even_ctr)
print("\nNumber of odd numbers in the above array: ", odd_ctr)
Sample Output:
Original arrays: [1, 2, 3, 5, 7, 8, 9, 10] Number of even numbers in the above array: 3 Number of odd numbers in the above array: 5
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Previous: Write a Python program to rearrange positive and negative numbers in a given array using Lambda.
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Python: Tips of the Day
Find current directory and file's directory:
To get the full path to the directory a Python file is contained in, write this in that file:
import os dir_path = os.path.dirname(os.path.realpath(__file__))
(Note that the incantation above won't work if you've already used os.chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os.chdir() call.)
To get the current working directory use
import os cwd = os.getcwd()
Documentation references for the modules, constants and functions used above:
- The os and os.path modules.
- The __file__ constant
- os.path.realpath(path) (returns "the canonical path of the specified filename, eliminating any symbolic links encountered in the path")
- os.path.dirname(path) (returns "the directory name of pathname path")
- os.getcwd() (returns "a string representing the current working directory")
- os.chdir(path) ("change the current working directory to path")
Ref: https://bit.ly/3fy0R6m
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