Python: Extract non_zero block from a given integers of list
Python Itertools: Exercise-44 with Solution
Write a Python program to extract non_zero block from a given integers of list.
Sample Solution:
Python Code:
import itertools as it
def test(lst):
result = [ list(x[1]) for x in it.groupby(lst, lambda x: x == 0) if not x[0] ]
return result
nums = [3,4,6,2,0,0,0,0,0,0,6,7,6,9,10,0,0,0,0,0,7,4,4,0,0,0,0,0,0,5,3,2,9,7,1]
print("\nOriginal list:")
print(nums)
print("\nExtract non_zero block from a given integers of list:")
print(test(nums))
Sample Output:
Original list: [3, 4, 6, 2, 0, 0, 0, 0, 0, 0, 6, 7, 6, 9, 10, 0, 0, 0, 0, 0, 7, 4, 4, 0, 0, 0, 0, 0, 0, 5, 3, 2, 9, 7, 1] Extract non_zero block from a given integers of list: [[3, 4, 6, 2], [6, 7, 6, 9, 10], [7, 4, 4], [5, 3, 2, 9, 7, 1]]
Python Code Editor:
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Find current directory and file's directory:
To get the full path to the directory a Python file is contained in, write this in that file:
import os dir_path = os.path.dirname(os.path.realpath(__file__))
(Note that the incantation above won't work if you've already used os.chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os.chdir() call.)
To get the current working directory use
import os cwd = os.getcwd()
Documentation references for the modules, constants and functions used above:
- The os and os.path modules.
- The __file__ constant
- os.path.realpath(path) (returns "the canonical path of the specified filename, eliminating any symbolic links encountered in the path")
- os.path.dirname(path) (returns "the directory name of pathname path")
- os.getcwd() (returns "a string representing the current working directory")
- os.chdir(path) ("change the current working directory to path")
Ref: https://bit.ly/3fy0R6m
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