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Python: Find the maximum, minimum aggregation pair in given list of integers

Python Itertools: Exercise-28 with Solution

Write a Python program to find the maximum, minimum aggregation pair in given list of integers.

Sample Solution:

Python Code:

from itertools import combinations 
def max_aggregate(l_data):
    max_pair = max(combinations(l_data, 2), key = lambda pair: pair[0] + pair[1])
    min_pair = min(combinations(l_data, 2), key = lambda pair: pair[0] + pair[1])
    return max_pair,min_pair
nums = [1,3,4,5,4,7,9,11,10,9]
print("Original list:")
print(nums)
result = max_aggregate(nums)
print("\nMaximum aggregation pair of the said list of tuple pair:")
print(result[0])
print("\nMinimum aggregation pair of the said list of tuple pair:")
print(result[1])

Sample Output:

Original list:
[1, 3, 4, 5, 4, 7, 9, 11, 10, 9]

Maximum aggregation pair of the said list of tuple pair:
(11, 10)

Minimum aggregation pair of the said list of tuple pair:
(1, 3)

Python Code Editor:


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Python: Tips of the Day

Find current directory and file's directory:

To get the full path to the directory a Python file is contained in, write this in that file:

import os 
dir_path = os.path.dirname(os.path.realpath(__file__))

(Note that the incantation above won't work if you've already used os.chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os.chdir() call.)

To get the current working directory use

import os
cwd = os.getcwd()

Documentation references for the modules, constants and functions used above:

  • The os and os.path modules.
  • The __file__ constant
  • os.path.realpath(path) (returns "the canonical path of the specified filename, eliminating any symbolic links encountered in the path")
  • os.path.dirname(path) (returns "the directory name of pathname path")
  • os.getcwd() (returns "a string representing the current working directory")
  • os.chdir(path) ("change the current working directory to path")

Ref: https://bit.ly/3fy0R6m