Python: Find the first two elements of a given list whose sum is equal to a given value
Python Itertools: Exercise-25 with Solution
Write a Python program to find the first two elements of a given list whose sum is equal to a given value. Use itertools module to solve the problem.
Sample Solution:
Python Code:
import itertools as it
def sum_pairs_list(nums, n):
for num2, num1 in list(it.combinations(nums[::-1], 2))[::-1]:
if num2 + num1 == n:
return [num1, num2]
nums = [1,2,3,4,5,6,7]
n = 10
print("Original list:",nums,": Given value:",n)
print("Sum of pair equal to ",n,"=",sum_pairs_list(nums,n))
nums = [1,2,-3,-4,-5,6,-7]
n = -6
print("Original list:",nums,": Given value:",n)
print("Sum of pair equal to ",n,"=",sum_pairs_list(nums,n))
Sample Output:
Original list: [1, 2, 3, 4, 5, 6, 7] : Given value: 10 Sum of pair equal to 10 = [4, 6] Original list: [1, 2, -3, -4, -5, 6, -7] : Given value: -6 Sum of pair equal to -6 = [1, -7]
Python Code Editor:
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Python: Tips of the Day
Find current directory and file's directory:
To get the full path to the directory a Python file is contained in, write this in that file:
import os dir_path = os.path.dirname(os.path.realpath(__file__))
(Note that the incantation above won't work if you've already used os.chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os.chdir() call.)
To get the current working directory use
import os cwd = os.getcwd()
Documentation references for the modules, constants and functions used above:
- The os and os.path modules.
- The __file__ constant
- os.path.realpath(path) (returns "the canonical path of the specified filename, eliminating any symbolic links encountered in the path")
- os.path.dirname(path) (returns "the directory name of pathname path")
- os.getcwd() (returns "a string representing the current working directory")
- os.chdir(path) ("change the current working directory to path")
Ref: https://bit.ly/3fy0R6m
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