Python: Compress repeated character by storing the length of a given string

Python Itertools: Exercise-17 with Solution

Write a Python program to read a given string character by character and compress repeated character by storing the length of those character(s).

Sample Solution:

Python Code:

from itertools import groupby
def encode_str(input_str):
    return [(len(list(n)), m) for m,n in groupby(input_str)]
 
str1 = "AAASSSSKKIOOOORRRREEETTTTAAAABBBBBBDDDDD" 
print("Original string:")
print(str1)
print("Result:")
print(encode_str(str1))

str1 = "jjjjiiiiooooosssnssiiiiwwwweeeaaaabbbddddkkkklll" 
print("\nOriginal string:")
print(str1)
print("Result:")
print(encode_str(str1))

Sample Output:

Original string:
AAASSSSKKIOOOORRRREEETTTTAAAABBBBBBDDDDD
Result:
[(3, 'A'), (4, 'S'), (2, 'K'), (1, 'I'), (4, 'O'), (4, 'R'), (3, 'E'), (4, 'T'), (4, 'A'), (6, 'B'), (5, 'D')]

Original string:
jjjjiiiiooooosssnssiiiiwwwweeeaaaabbbddddkkkklll
Result:
[(4, 'j'), (4, 'i'), (5, 'o'), (3, 's'), (1, 'n'), (2, 's'), (4, 'i'), (4, 'w'), (3, 'e'), (4, 'a'), (3, 'b'), (4, 'd'), (4, 'k'), (3, 'l')]

Python Code Editor:

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