Python: Count the frequency in a given dictionary
Python dictionary: Exercise-61 with Solution
Write a Python program to count the frequency in a given dictionary.
Sample Solution:
Python Code:
from collections import Counter
def test(dictt):
result = Counter(dictt.values())
return result
dictt = {
'V': 10,
'VI': 10,
'VII': 40,
'VIII': 20,
'IX': 70,
'X': 80,
'XI': 40,
'XII': 20,
}
print("\nOriginal Dictionary:")
print(dictt)
print("\nCount the frequency of the said dictionary:")
print(test(dictt))
Sample Output:
Original Dictionary: {'V': 10, 'VI': 10, 'VII': 40, 'VIII': 20, 'IX': 70, 'X': 80, 'XI': 40, 'XII': 20} Count the frequency of the said dictionary: Counter({10: 2, 40: 2, 20: 2, 70: 1, 80: 1})
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Python: Tips of the Day
Find current directory and file's directory:
To get the full path to the directory a Python file is contained in, write this in that file:
import os dir_path = os.path.dirname(os.path.realpath(__file__))
(Note that the incantation above won't work if you've already used os.chdir() to change your current working directory, since the value of the __file__ constant is relative to the current working directory and is not changed by an os.chdir() call.)
To get the current working directory use
import os cwd = os.getcwd()
Documentation references for the modules, constants and functions used above:
- The os and os.path modules.
- The __file__ constant
- os.path.realpath(path) (returns "the canonical path of the specified filename, eliminating any symbolic links encountered in the path")
- os.path.dirname(path) (returns "the directory name of pathname path")
- os.getcwd() (returns "a string representing the current working directory")
- os.chdir(path) ("change the current working directory to path")
Ref: https://bit.ly/3fy0R6m
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