Python Bisect: Find three integers which gives the sum of zero in a given array of integers using Binary Search

Python Bisect: Exercise-7 with Solution

Write a Python program to find three integers which gives the sum of zero in a given array of integers using Binary Search (bisect).

Sample Solution:

Python Code:

from bisect import bisect, bisect_left
from collections import Counter
class Solution:
    def three_Sum(self, nums):
        """
        :type nums: List[int]
        :rtype: List[List[int]]
        """
        triplets = []
        if len(nums) < 3:
            return triplets
        num_freq = Counter(nums)
        nums = sorted(num_freq)  # Sorted unique numbers
        max_num = nums[-1]
        for i, v in enumerate(nums):
            if num_freq[v] >= 2:
                complement =  -2 * v
                if complement in num_freq:
                    if complement != v or num_freq[v] >= 3:
                        triplets.append([v] * 2 + [complement])

            # When all 3 numbers are different.
            if v < 0:  # Only when v is the smallest
                two_sum = -v

                # Lower/upper bound of the smaller of remainingtwo.
                lb = bisect_left(nums, two_sum - max_num, i + 1)
                ub = bisect(nums, two_sum // 2, lb)                       
                for u in nums[lb : ub]:
                    complement = two_sum - u
                    if complement in num_freq and u != complement:
                        triplets.append([v, u, complement])
        return triplets
nums = [-20, 0, 20, 40, -20, -40, 80]
s = Solution()
result = s.three_Sum(nums)
print(result)
nums = [1, 2, 3, 4, 5, -6]
result = s.three_Sum(nums)
print(result)

Sample Output:

[[-40, 0, 40], [-20, -20, 40], [-20, 0, 20]]
[[-6, 1, 5], [-6, 2, 4]]

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