PostgreSQL Aggregate Functions and Group By: Find the manager ID and the salary of the lowest-paid employee under that manager
9. Write a query to find the manager ID and the salary of the lowest-paid employee under that manager.
Sample Solution:
Code:
SELECT manager_id, MIN(salary)
FROM employees
WHERE manager_id IS NOT NULL
GROUP BY manager_id
ORDER BY MIN(salary) DESC;
Sample table: employees
Output:
pg_exercises=# SELECT manager_id, MIN(salary) pg_exercises-# FROM employees pg_exercises-# WHERE manager_id IS NOT NULL pg_exercises-# GROUP BY manager_id pg_exercises-# ORDER BY MIN(salary) DESC; manager_id | min ------------+---------- 0 | 24000.00 102 | 9000.00 205 | 8300.00 145 | 7000.00 146 | 7000.00 108 | 6900.00 147 | 6200.00 149 | 6200.00 148 | 6100.00 201 | 6000.00 100 | 5800.00 101 | 4400.00 103 | 4200.00 123 | 2500.00 124 | 2500.00 114 | 2500.00 120 | 2200.00 122 | 2200.00 121 | 2100.00 (19 rows)
Relational Algebra Expression:
Relational Algebra Tree:
Practice Online
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Previous: Write a query to get the difference between the highest and lowest salaries.
Next: Write a query to get the department ID and the total salary payable in each department.
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