PHP Exercises: Reads an integer n and find the number of combinations
PHP: Exercise-51 with Solution
Write a PHP program which reads an integer n and find the number of combinations of a,b,c and d (0 ≤ a,b,c,d ≤ 9) where (a + b + c + d) will be equal to n.
Input:
n (1 ≤ n ≤ 50) .
Sample Solution: -
PHP Code:
<?php
while (($input = trim(fgets(STDIN))) !== '') {
$input = intval($input);
$count = 0;
for ($i=0; $i < 10; $i++) {
for ($j=0; $j < 10; $j++) {
for ($k=0; $k < 10; $k++) {
for ($l=0; $l < 10; $l++) {
if ($i + $j + $k +$l === $input) {
$count++;
}
}
}
}
}
echo "\nNumber of combinations of a,b,c and d: ";
echo $count."\n";
}
?>
Sample Output:
Number of combinations of a,b,c and d: 56
Flowchart:
PHP Code Editor:
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Previous: Write a PHP program to compute the amount of the debt in n months.
Next: Write a PHP program to print the number of prime numbers which are less than or equal to a given integer.
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PHP: Tips of the Day
How to Sort Multi-dimensional Array by Value?
Try a usort, If you are still on PHP 5.2 or earlier, you'll have to define a sorting function first:
Example:
function sortByOrder($a, $b) { return $a['order'] - $b['order']; } usort($myArray, 'sortByOrder');
Starting in PHP 5.3, you can use an anonymous function:
usort($myArray, function($a, $b) { return $a['order'] - $b['order']; });
And finally with PHP 7 you can use the spaceship operator:
usort($myArray, function($a, $b) { return $a['order'] <=> $b['order']; });
To extend this to multi-dimensional sorting, reference the second/third sorting elements if the first is zero - best explained below. You can also use this for sorting on sub-elements.
usort($myArray, function($a, $b) { $retval = $a['order'] <=> $b['order']; if ($retval == 0) { $retval = $a['suborder'] <=> $b['suborder']; if ($retval == 0) { $retval = $a['details']['subsuborder'] <=> $b['details']['subsuborder']; } } return $retval; });
If you need to retain key associations, use uasort() - see comparison of array sorting functions in the manual
Ref : https://bit.ly/3i77vCC
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