PHP Exercises: Check if an array of integers contains a 3 next to a 3 or a 5 next to a 5 or both
PHP Basic Algorithm: Exercise-116 with Solution
Write a PHP program to check if an array of integers contains a 3 next to a 3 or a 5 next to a 5 or both.
Sample Solution:
PHP Code :
<?php
function test($numbers)
{
for ($i = 0; $i < sizeof($numbers) - 1; $i++)
if (($numbers[$i] == 3 && $numbers[$i + 1] == 3) || ($numbers[$i] == 5 && $numbers[$i] == 5))
return true;
return false;
}
var_dump(test([5, 5, 5, 5, 5]));
var_dump(test([1, 2, 3, 4]));
var_dump(test([3, 3, 5, 5, 5, 5]));
var_dump(test([1, 5, 5, 7, 8, 10]));
Sample Output:
bool(true) bool(false) bool(true) bool(true)
Flowchart:
PHP Code Editor:
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Previous: Write a PHP program to check if a given array of integers contains no 3 or a 5.
Next: Write a PHP program to check a given array of integers and return true if the given array contains two 5's next to each other, or two 5 separated by one element.
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PHP: Tips of the Day
How to Sort Multi-dimensional Array by Value?
Try a usort, If you are still on PHP 5.2 or earlier, you'll have to define a sorting function first:
Example:
function sortByOrder($a, $b) { return $a['order'] - $b['order']; } usort($myArray, 'sortByOrder');
Starting in PHP 5.3, you can use an anonymous function:
usort($myArray, function($a, $b) { return $a['order'] - $b['order']; });
And finally with PHP 7 you can use the spaceship operator:
usort($myArray, function($a, $b) { return $a['order'] <=> $b['order']; });
To extend this to multi-dimensional sorting, reference the second/third sorting elements if the first is zero - best explained below. You can also use this for sorting on sub-elements.
usort($myArray, function($a, $b) { $retval = $a['order'] <=> $b['order']; if ($retval == 0) { $retval = $a['suborder'] <=> $b['suborder']; if ($retval == 0) { $retval = $a['details']['subsuborder'] <=> $b['details']['subsuborder']; } } return $retval; });
If you need to retain key associations, use uasort() - see comparison of array sorting functions in the manual
Ref : https://bit.ly/3i77vCC
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