PHP Exercises: Check if a given array of integers contains a 3 or a 5

Last update on May 30 2022 11:41:05 (UTC/GMT +8 hours)

PHP Basic Algorithm: Exercise-114 with Solution

Write a PHP program to check if a given array of integers contains a 3 or a 5.

Sample Solution:

PHP Code :

<?php
function test($nums)
 { 

     for ($i = 0; $i < sizeof($nums); $i++)
        {
            if ($nums[$i] != 3 && $nums[$i] != 5) return false;
         }
        return true;
 }   

var_dump(test([5, 5, 5, 5, 5]));
var_dump(test([3, 3, 3, 3]));
var_dump(test([3, 3, 3, 5, 5, 5]));
var_dump(test([1, 6, 8, 10]));

Sample Output:

bool(true)
bool(true)
bool(true)
bool(false)

Flowchart:

PHP Code Editor:

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Previous: Write a PHP program to check if the number of 3's is greater than the number of 5's.
Next: Write a PHP program to check if a given array of integers contains no 3 or a 5.

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PHP: Tips of the Day

How to Sort Multi-dimensional Array by Value?

Try a usort, If you are still on PHP 5.2 or earlier, you'll have to define a sorting function first:

Example:

function sortByOrder($a, $b) {
    return $a['order'] - $b['order'];
}

usort($myArray, 'sortByOrder');

Starting in PHP 5.3, you can use an anonymous function:

usort($myArray, function($a, $b) {
    return $a['order'] - $b['order'];
});

And finally with PHP 7 you can use the spaceship operator:

usort($myArray, function($a, $b) {
    return $a['order'] <=> $b['order'];
});

To extend this to multi-dimensional sorting, reference the second/third sorting elements if the first is zero - best explained below. You can also use this for sorting on sub-elements.

usort($myArray, function($a, $b) {
    $retval = $a['order'] <=> $b['order'];
    if ($retval == 0) {
        $retval = $a['suborder'] <=> $b['suborder'];
        if ($retval == 0) {
            $retval = $a['details']['subsuborder'] <=> $b['details']['subsuborder'];
        }
    }
    return $retval;
});

If you need to retain key associations, use uasort() - see comparison of array sorting functions in the manual

Ref : https://bit.ly/3i77vCC