PHP Exercises: Create a new array from two give array of integers, each length 3

Last update on May 30 2022 11:41:41 (UTC/GMT +8 hours)

PHP Basic Algorithm: Exercise-101 with Solution

Write a PHP program to create a new array from two give array of integers, each length 3.

Sample Solution:

PHP Code :

<?php
function test($nums1, $nums2)
 { 

     return [$nums1[0], $nums1[1], $nums1[2], $nums2[0], $nums2[1], $nums2[2]];
 }   

$result = test([10, 20, 30], [ 40, 50, 60] );
echo "New array: " . implode(',', $result);

Sample Output:

New array: 10,20,30,40,50,60

Flowchart:

PHP Code Editor:

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Previous: Write a PHP program to create an array taking two middle elements from a given array of integers of length even.
Next: Write a PHP program to create a new array swapping the first and last elements of a given array of integers and length will be least 1.

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PHP: Tips of the Day

How to Sort Multi-dimensional Array by Value?

Try a usort, If you are still on PHP 5.2 or earlier, you'll have to define a sorting function first:

Example:

function sortByOrder($a, $b) {
    return $a['order'] - $b['order'];
}

usort($myArray, 'sortByOrder');

Starting in PHP 5.3, you can use an anonymous function:

usort($myArray, function($a, $b) {
    return $a['order'] - $b['order'];
});

And finally with PHP 7 you can use the spaceship operator:

usort($myArray, function($a, $b) {
    return $a['order'] <=> $b['order'];
});

To extend this to multi-dimensional sorting, reference the second/third sorting elements if the first is zero - best explained below. You can also use this for sorting on sub-elements.

usort($myArray, function($a, $b) {
    $retval = $a['order'] <=> $b['order'];
    if ($retval == 0) {
        $retval = $a['suborder'] <=> $b['suborder'];
        if ($retval == 0) {
            $retval = $a['details']['subsuborder'] <=> $b['details']['subsuborder'];
        }
    }
    return $retval;
});

If you need to retain key associations, use uasort() - see comparison of array sorting functions in the manual

Ref : https://bit.ly/3i77vCC