MySQL Subquery Exercises: Find the name and salary of the employees whose salary is greater than the average salary

MySQL Subquery: Exercise-5 with Solution

Write a query to find the name (first_name, last_name), and salary of the employees whose salary is greater than the average salary.

Sample table: employees

Code:

SELECT first_name, last_name, salary FROM employees 
WHERE salary > (SELECT AVG(salary) FROM employees);

Explanation:

MySQL Subquery Syntax:

- The subquery (inner query) executes once before the main query (outer query) executes.
- The main query (outer query) use the subquery result.

MySQL AVG() function returns the average value of a set of values or an expression.

MySQL Code Editor:

Structure of 'hr' database :

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