MySQL Subquery Exercises: Find the name and salary of the employees who earn more than the average salary and works in any of the IT departments

MySQL Subquery: Exercise-7 with Solution

Write a query to find the name (first_name, last_name), and salary of the employees who earns more than the average salary and works in any of the IT departments.

Sample table: employees

Sample table : departments

Code:

SELECT first_name, last_name, salary 
FROM employees 
WHERE department_id IN 
(SELECT department_id FROM departments WHERE department_name LIKE 'IT%') 
AND salary > (SELECT avg(salary) FROM employees);

Explanation:

MySQL Subquery Syntax:

- The subquery (inner query) executes once before the main query (outer query) executes.
- The main query (outer query) use the subquery result.

MySQL Code Editor:

Structure of 'hr' database :

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