JavaScript Searching and Sorting Algorithm: Sort an array of objects, ordered by properties and orders

JavaScript Searching and Sorting Algorithm: Exercise-16 with Solution

Write a JavaScript program to sort an array of objects, ordered by properties and orders.

• Uses Array.prototype.sort(), Array.prototype.reduce() on the props array with a default value of 0.
• Use array destructuring to swap the properties position depending on the order supplied.
• If no orders array is supplied, sort by 'asc' by default.

Sample Solution:

JavaScript Code:

const orderBy = (arr, props, orders) =>
  [...arr].sort((a, b) =>
    props.reduce((acc, prop, i) => {
      if (acc === 0) {
        const [p1, p2] =
          orders && orders[i] === 'desc'
            ? [b[prop], a[prop]]
            : [a[prop], b[prop]];
        acc = p1 > p2 ? 1 : p1 < p2 ? -1 : 0;
      }
      return acc;
    }, 0)
  );

const users = [
  { name: 'fred', age: 48 },
  { name: 'barney', age: 36 },
  { name: 'fred', age: 40 },
];
console.log(orderBy(users, ['name', 'age'], ['asc', 'desc']));
console.log(orderBy(users, ['name', 'age']));

Sample Output:

[{"name":"barney","age":36},{"name":"fred","age":48},{"name":"fred","age":40}]
[{"name":"barney","age":36},{"name":"fred","age":40},{"name":"fred","age":48}]

Flowchart:

Live Demo:

See the Pen javascript-common-editor by w3resource (@w3resource) on CodePen.

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