JavaScript: Check whether the characters a and b are separated by exactly 3 places anywhere in a given string
JavaScript Basic: Exercise-53 with Solution
Write a JavaScript program to check whether the characters a and b are separated by exactly 3 places anywhere (at least once) in a given string.
Pictorial Presentation:
Sample Solution:
HTML Code:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JavaScript program to check whether the characters a and b are separated by exactly 3 places anywhere (at least once) in a given string.</title>
</head>
<body>
</body>
</html>
JavaScript Code:
function ab_Check(str)
{
return (/a...b/).test(str) || (/b...a/).test(str);
}
console.log(ab_Check("Chainsbreak"));
console.log(ab_Check("pane borrowed"));
console.log(ab_Check("abCheck"));
Sample Output:
true true false
Flowchart:
ES6 Version:
function ab_Check(str)
{
return (/a...b/).test(str) || (/b...a/).test(str);
}
console.log(ab_Check("Chainsbreak"));
console.log(ab_Check("pane borrowed"));
console.log(ab_Check("abCheck"));
Live Demo:
See the Pen JavaScript - Check whether the characters a and b are separated by exactly 3 places - basic-ex-53 by w3resource (@w3resource) on CodePen.
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Previous: Write a JavaScript program to convert the letters of a given string in alphabetical order.
Next: Write a JavaScript program to count the number of vowels of a given string.
What is the difficulty level of this exercise?
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JavaScript: Tips of the Day
How to insert an item into an array at a specific index (JavaScript)?
What you want is the splice function on the native array object.
arr.splice(index, 0, item); will insert item into arr at the specified index (deleting 0 items first, that is, it's just an insert). In this example we will create an array and add an element to it into index 2:
var arr = []; arr[0] = "Jani"; arr[1] = "Hege"; arr[2] = "Stale"; arr[3] = "Kai Jim"; arr[4] = "Borge"; console.log(arr.join()); arr.splice(2, 0, "Lene"); console.log(arr.join());
Ref: https://bit.ly/2BXbp04
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