JavaScript: Check whether all the digits in a given number are the same or not
JavaScript Basic: Exercise-140 with Solution
Write a JavaScript program to check whether all the digits in a given number are the same or not.
Pictorial Presentation:
Sample Solution:
HTML Code:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>Check whether all the digits in a given number are the same or not</title>
</head>
<body>
</body>
</html>
JavaScript Code:
function test_same_digit(num) {
var first = num % 10;
while (num) {
if (num % 10 !== first) return false;
num = Math.floor(num / 10);
}
return true
}
console.log(test_same_digit(1234));
console.log(test_same_digit(1111));
console.log(test_same_digit(22222222));
Sample Output:
false true true
Flowchart:
ES6 Version:
function test_same_digit(num) {
const first = num % 10;
while (num) {
if (num % 10 !== first) return false;
num = Math.floor(num / 10);
}
return true
}
console.log(test_same_digit(1234));
console.log(test_same_digit(1111));
console.log(test_same_digit(22222222));
Live Demo:
See the Pen javascript-basic-exercise-140 by w3resource (@w3resource) on CodePen.
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Previous:Write a JavaScript program to find the position of a rightmost round number in an array of integers. Returns 0 if there are no round number.
Next: Write a JavaScript program to find the number of elements which presents in both of the given arrays.
What is the difficulty level of this exercise?
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JavaScript: Tips of the Day
How to insert an item into an array at a specific index (JavaScript)?
What you want is the splice function on the native array object.
arr.splice(index, 0, item); will insert item into arr at the specified index (deleting 0 items first, that is, it's just an insert). In this example we will create an array and add an element to it into index 2:
var arr = []; arr[0] = "Jani"; arr[1] = "Hege"; arr[2] = "Stale"; arr[3] = "Kai Jim"; arr[4] = "Borge"; console.log(arr.join()); arr.splice(2, 0, "Lene"); console.log(arr.join());
Ref: https://bit.ly/2BXbp04
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