Java String Exercises: Find the longest mirror image string at the both ends of a given string
Java String: Exercise-94 with Solution
Write a Java program to find the longest mirror image string at the both ends of a given string.
Sample Solution:
Java Code:
import java.util.*;
public class Main
{
public String endsWithMirrorImage(String stng)
{
int l = stng.length();
String f_str = "";
String t_str1 = "";
String t_str2 = "";
for (int i = 0; i < l; i++)
{
t_str1 += stng.substring(i,i+1);
t_str2 = "";
for (int j = t_str1.length()-1; j >= 0; j--)
{
t_str2 += t_str1.substring(j,j+1);
if (t_str2.equals(stng.substring(l-i-1,l)))
f_str = t_str1;
}
}
return f_str;
}
public static void main (String[] args)
{
Main m= new Main();
String str1 = "rotavator";
System.out.println("The given string is: "+str1);
System.out.println("The longest mirror image string in the string is: "+m.endsWithMirrorImage(str1));
}
}
Sample Output:
The given string is: rotavator The longest mirror image string in the string is: rotavator
Pictorial Presentation:
Flowchart:
Java Code Editor:
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Next: Write a Java program to return the sum of the digits present in the given string. If there is no digits the sum return is 0.
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