Java Conditional Statement Exercises: Find Vowel or Consonant
Java Conditional Statement: Exercise-8 with Solution
Write a Java program that takes the user to provide a single character from the alphabet. Print Vowel of Consonant, depending on the user input. If the user input is not a letter (between a and z or A and Z), or is a string of length > 1, print an error message.
Test Data
Input an alphabet: p
Pictorial Presentation:
Sample Solution:
Java Code:
import java.util.Scanner;
public class Exercise8 {
public static void main(String[] args)
{
Scanner in = new Scanner(System.in);
System.out.print("Input an alphabet: ");
String input = in.next().toLowerCase();
boolean uppercase = input.charAt(0) >= 65 && input.charAt(0) <= 90;
boolean lowercase = input.charAt(0) >= 97 && input.charAt(0) <= 122;
boolean vowels = input.equals("a") || input.equals("e") || input.equals("i")
|| input.equals("o") || input.equals("u");
if (input.length() > 1)
{
System.out.println("Error. Not a single character.");
}
else if (!(uppercase || lowercase))
{
System.out.println("Error. Not a letter. Enter uppercase or lowercase letter.");
}
else if (vowels)
{
System.out.println("Input letter is Vowel");
}
else
{
System.out.println("Input letter is Consonant");
}
}
}
Sample Output:
Input an alphabet: P Input letter is Consonant
Flowchart:
Java Code Editor:
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