Java Exercises: Test if an array of integers contains an element 10 next to 10 or an element 20 next to 20, but not both

Java Basic: Exercise-93 with Solution

Write a Java program to test if an array of integers contains an element 10 next to 10 or an element 20 next to 20, but not both.

Sample Solution:

Java Code:

import java.util.*; 
public class Exercise93 {
 public static void main(String[] args)
 {
    //int[] nums = {10, 10, 2, 4, 9};
	int[] nums = {10, 10, 2, 4, 20, 20};  
	int ctr_even = 0, ctr_odd = 0;
	System.out.println("Original Array: "+Arrays.toString(nums)); 
	    
    boolean found1010 = false;
    boolean found2020 = false;
      
    for(int i = 0; i < nums.length - 1; i++) {
        if(nums[i] == 10 && nums[i+1] == 10)
            found1010 = true;
                        
        if(nums[i] == 20 && nums[i+1] == 20)
            found2020 = true;
    }
   
	System.out.printf( String.valueOf(found1010 != found2020));	
	System.out.printf("\n");
  }
}

Sample Output:

Original Array: [10, 10, 2, 4, 20, 20]                                 
false 

Pictorial Presentation:

Flowchart:

Java Code Editor:

Contribute your code and comments through Disqus.

Previous: Write a Java program to count the number of even and odd elements in a given array of integers.
Next: Write a Java program to rearrange all the elements of an given array of integers so that all the odd numbers come before all the even numbers.