Java Exercises: Find all the start indices of a given string's anagrams in another specified string
Java Basic: Exercise-188 with Solution
Write a Java program to find all the start indices of a given string's anagrams in another given string.
Pictorial Presentation:
Sample Solution:
Java Code:
import java.util.*;
public class Solution {
public static void main(String[] args) {
String str1 = "zyxwyxyxzwxyz";
String str2 = "xyz";
System.out.println("Original String: " + str1);
System.out.println("Starting anagram indices of " + str2 + ": " + find_Anagrams(str1, str2));
}
public static List < Integer > find_Anagrams(String str1, String str2) {
List < Integer > list = new ArrayList < Integer > ();
if (str1.length() < str2.length() || str2.length() < 1) {
return list;
}
if (str1.equals(str2)) {
list.add(0);
return list;
}
HashMap < Character, Integer > map = new HashMap < > ();
for (char c: str2.toCharArray()) {
if (map.containsKey(c)) {
map.put(c, map.get(c) + 1);
} else {
map.put(c, 1);
}
}
int str2_length = str2.length();
int current_length = 0;
int correct_chars = 0;
for (int i = 0; i < str1.length(); ++i) {
current_length++;
if (map.containsKey(str1.charAt(i))) {
int ctr = map.get(str1.charAt(i));
if (ctr > 0) {
correct_chars++;
}
map.put(str1.charAt(i), ctr - 1);
}
if (current_length == str2_length) {
int begin_pos = i - str2_length + 1;
if (correct_chars == str2_length) {
list.add(begin_pos);
}
if (map.containsKey(str1.charAt(begin_pos))) {
int ctr = map.get(str1.charAt(begin_pos));
if (ctr >= 0) {
correct_chars--;
}
map.put(str1.charAt(begin_pos), ctr + 1);
}
current_length--;
}
}
return list;
}
}
Sample Output:
Original String: zyxwyxyxzwxyz Starting anagram indices of xyz: [0, 6, 10]
Flowchart:
Java Code Editor:
Company: Amazon
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Previous: Write a Java program to find the index of first non-repeating character in a given string.
Next: Write a Java program to Given two non-negative integers num1 and num2 represented as string, return the sum of num1 and num2.
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