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Java Exercises: Partition an given array of integers into even number first and odd number second

Java Basic: Exercise-176 with Solution

Write a Java program to partition an given array of integers into even number first and odd number second.

Original array: [7, 2, 4, 1, 3, 5, 6, 8, 2, 10]
After partition the said array becomes: [10, 2, 4, 2, 8, 6, 5, 3, 1, 7]

Pictorial Presentation:

Java Basic Exercises: Partition an given array of integers into even number first and odd number second.

Sample Solution:

Java Code:

import java.util.*;

public class Solution {  
	
    public static void main(String[] args) {
		int[] nums = {7, 2, 4, 1, 3, 5, 6, 8, 2, 10};
		System.out.println("Original array: "+Arrays.toString(nums));
     	int[] result = partitionArray2(nums);
        System.out.println("After partition the said array becomes: " +Arrays.toString(result));
      }

   

    public static int[] partitionArray2(int[] nums) {
        int i = 0;
        int j = nums.length - 1;
        while (i < j) {
            while (nums[i] % 2 == 0) i++;
            while (nums[j] % 2 != 0) j--;
            if (i < j) {
                int temp = nums[i];
                nums[i] = nums[j];
                nums[j] = temp;
            }
        }
		return nums;
    }
}

Sample Output:

Original array: [7, 2, 4, 1, 3, 5, 6, 8, 2, 10]
After partition the said array becomes: [10, 2, 4, 2, 8, 6, 5, 3, 1, 7]

Flowchart:

Flowchart: Java exercises: Partition an given array of integers into even number first and odd number second.

Java Code Editor:

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Java: Tips of the Day

How to sort an ArrayList?

Collections.sort(testList);
Collections.reverse(testList);

That will do what you want. Remember to import Collections though!

Ref: https://bit.ly/32urdSe