Java Exercises: Check if a specified array of integers contains 10 or 30
Java Basic: Exercise-102 with Solution
Write a Java program to check if a specified array of integers contains 10 or 30.
Pictorial Presentation:
Sample Solution:
Java Code:
import java.util.*;
import java.io.*;
public class Exercise102 {
public static void main(String[] args)
{
int[] array_nums = {11, 11, 13, 31, 45, 20, 33, 53};
int result = 1;
System.out.println("Original Array: "+Arrays.toString(array_nums));
for(int i = 0; i < array_nums.length; i++)
{
if(array_nums[i] == 10 || array_nums[i] == 30)
{
result =0;
}
}
if (result==1)
System.out.printf( String.valueOf(false));
else
System.out.printf(String.valueOf(true));
}
}
Sample Output:
Original Array: [11, 11, 13, 31, 45, 20, 33, 53] false
Flowchart:
Java Code Editor:
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Previous: Write a Java program to check if the number of 10 is greater than number to 20 in a given array of integers.
Next: Write a Java program to create a new array from a given array of integers, new array will contain the elements from the given array after the last element value 10.
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Java: Tips of the Day
How to sort an ArrayList?
Collections.sort(testList); Collections.reverse(testList);
That will do what you want. Remember to import Collections though!
Ref: https://bit.ly/32urdSe
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