Java Exercises: Count the two elements of two given arrays of integers with same length, differ by 1 or less

Java Basic: Exercise-100 with Solution

Write a Java program to count the two elements of two given arrays of integers with same length, differ by 1 or less.

Pictorial Presentation:

Sample Solution:

Java Code:

import java.util.*; 
import java.io.*; 
 public class Exercise100 {
 public static void main(String[] args)
 {
	int[] array_nums1 = {10, 11, 10, 20, 43, 20, 50};
	int[] array_nums2 = {10, 13, 11, 20, 44, 30, 50};
	System.out.println("Array1: "+Arrays.toString(array_nums1)); 
	System.out.println("Array2: "+Arrays.toString(array_nums2)); 
	int ctr = 0;
    
    for(int i = 0; i < array_nums1.length; i++) {
        if(Math.abs(array_nums1[i] - array_nums2[i]) <= 1 && array_nums1[i] != array_nums2[i])
            ctr++;
    }
                    
    System.out.printf("Number of elements: "+ctr);
	System.out.printf("\n");	 
  }
}

Sample Output:

Array1: [10, 11, 10, 20, 43, 20, 50]                                   
Array2: [10, 13, 11, 20, 44, 30, 50]                                   
Number of elements: 2

Flowchart:

Java Code Editor:

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