Java Array Exercises: Rearrange a given array of unique elements such that every second element of the array is greater than its left and right elements
Java Array: Exercise-61 with Solution
Write a Java program to rearrange a given array of unique elements such that every second element of the array is greater than its left and right elements.
Example:
Input :
nums= { 1, 2, 4, 9, 5, 3, 8, 7, 10, 12, 14 }
Output:
Array with every second element is greater than its left and right elements:
[1, 4, 2, 9, 3, 8, 5, 10, 7, 14, 12]
Sample Solution:
Java Code:
import java.util.Arrays;
class solution
{
private static void swap_nums(int[] nums, int i, int j) {
int t_nums = nums[i];
nums[i] = nums[j];
nums[j] = t_nums;
}
public static void rearrange_Array_nums(int[] nums)
{
for (int i = 1; i < nums.length; i += 2)
{
if (nums[i - 1] > nums[i]) {
swap_nums(nums, i - 1, i);
}
if (i + 1 < nums.length && nums[i + 1] > nums[i]) {
swap_nums(nums, i + 1, i);
}
}
}
public static void main (String[] args)
{
int[] nums= { 1, 2, 4, 9, 5, 3, 8, 7, 10, 12, 14 };
System.out.println("Original array:\n"+Arrays.toString(nums));
rearrange_Array_nums(nums);
System.out.println("\nArray with every second element is greater than its left and right elements:\n"+Arrays.toString(nums));
}
}
Sample Output:
Original array: [1, 2, 4, 9, 5, 3, 8, 7, 10, 12, 14] Array with every second element is greater than its left and right elements: [1, 4, 2, 9, 3, 8, 5, 10, 7, 14, 12]
Flowchart:
Java Code Editor:
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Next: Write a Java program to find the equilibrium indices from a given array of integers.
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Java: Tips of the Day
How to sort an ArrayList?
Collections.sort(testList); Collections.reverse(testList);
That will do what you want. Remember to import Collections though!
Ref: https://bit.ly/32urdSe
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