C# Sharp Exercises: Accept the members of a list and display the members more than a specific value
C# Sharp LINQ : Exercise-10 with Solution
Write a program in C# Sharp to accept the members of a list through the keyboard and display the members more than a specific value.
Sample Solution:-
C# Sharp Code:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
class LinqExercise10
{
static void Main(string[] args)
{
int i=0;
int memlist,n,m;
List<int> templist = new List<int>();
Console.Write("\nLINQ : Accept the members of a list and display the members more than a specific value : ");
Console.Write("\n----------------------------------------------------------------------------------------\n");
Console.Write("Input the number of members on the List : ");
n= Convert.ToInt32(Console.ReadLine());
for(i=0;i<n;i++)
{
Console.Write("Member {0} : ",i);
memlist= Convert.ToInt32(Console.ReadLine());
templist.Add(memlist);
}
Console.Write("\nInput the value above you want to display the members of the List : ");
m = Convert.ToInt32(Console.ReadLine());
List<int> FilterList = templist.FindAll(x => x > m ? true : false);
Console.WriteLine("\nThe numbers greater than {0} are : ",m);
foreach (var num in FilterList)
{
Console.WriteLine(num);
}
Console.ReadLine();
}
}
Sample Output:
LINQ : Accept the members of a list and display the members more than a specific value : ---------------------------------------------------------------------------------------- Input the number of members on the List : 5 Member 0 : 10 Member 1 : 20 Member 2 : 30 Member 3 : 40 Member 4 : 50 Input the value above you want to display the members of the List : 20 The numbers greater than 20 are : 30 40 50
Pictorial Presentation:
Flowchart:
C# Sharp Code Editor:
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