C# Sharp Basic Algorithm Exercises: Shift an element in left direction and return a new array
C# Sharp Basic Algorithm: Exercise-127 with Solution
Write a C# Sharp program to shift an element in left direction and return a new array.
Pictorial Presentation:
Sample Solution:
C# Sharp Code:
using System;
namespace exercises
{
class Program
{
static void Main(string[] args)
{
int[] item = test(new[] { 10, 20, -30, -40, 50 });
Console.Write("New array: ");
foreach(var i in item)
{
Console.Write(i.ToString()+" ");
}
}
static int[] test(int[] numbers)
{
int size = numbers.Length;
int[] shiftNums = new int[size];
for (int i = 0; i < size; i++)
{
shiftNums[i] = numbers[(i + 1) % size];
}
return shiftNums;
}
}
}
Sample Output:
New array: 20 -30 -40 50 10
Flowchart:
C# Sharp Code Editor:
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Previous: Write a C# Sharp program to check a given array of integers and return true if the array contains three increasing adjacent numbers.
Next: Write a C# Sharp program to create a new array taking the elements before the element value 5 from a given array of integers.
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