C++ Exercises: Check whether a given number is an Armstrong number or not

C++ Numbers: Exercise-43 with Solution

Write a C++ program to check whether a given number is an Armstrong number or not.

/*When the sum of the cube of the individual digits of a number
is equal to that number, the number is called Armstrong number. For example 153.
Sum of its divisor is 13 + 53;+ 33; = 1+125+27 = 153*/

Sample Solution:

C++ Code:

#include <iostream>
using namespace std;

int main()
{
    int num, r, sum = 0, temp;
    cout << "\n\n Check whether a given number is an Armstrong number or not :\n";
    cout << "-----------------------------------------------------------------\n";
    cout << " Input a number: ";
    cin >> num;
    for (temp = num; num != 0; num = num / 10) 
	{
        r = num % 10;
        sum = sum + (r * r * r);
    }
    if (sum == temp)
        cout << temp << " is an Armstrong number." << endl;
    else
        cout << temp << " is not an Armstrong number." << endl;
}

Sample Output:

Check whether a given number is an Armstrong number or not:                                                
 -------------------------------------------------------                                             
  Input a number: 153    
153 is an Armstrong number

Flowchart:

C++ Code Editor:

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